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I'm trying to write an svg filter to render wavelight over the given shape. So, inside this shape, the general rule is that the waves are applied, but i don't want to have a visible effect outside of this shape. As far as i understand, i can't just use the same image source either for the heightmap used for the waves or as the target domain for the top music. So i thought the element could be used to access the heightmap from a separate object with a gradient fill. But i haven't been able to make this object visible inside the filter effect area yet. First try The code i have:Related documentation Documentation for states: If 'xlink:href' refers to a standalone image resource such as a jpeg, png or svg file, then the image pad is rendered after the behavior of the "image" element is styled; otherwise, the specified resource is rendered according to the behavior of the "use" element. Under any conditions, the current custom coordinate system depends on the value of the 'primitiveunits' attribute on the 'filter' element. Second attempt Use image instead looks good to me, but i'm not sure how the rectangular area is defined in that case. The documentation, according to usage, probably indicates how in this case (the log being referenced is neither a character nor an svg element), the dimension properties don't matter, but how does that describe a rectangular area? I also thought that maybe changing the primitive units would help. Or boxing an image inside a symbol. So my second attempt was as follows: The image is still not visible. What am i doing wrong? Basic question How can i use a fragment of my svg movie as a bump map for lighting without also using it as the sourcegraphic of my filter? Rasterizer This image is not intended for web deployment, but will be rasterized locally. So, browser support is not considered a big problem; if the thing renders correctly in inkscape or rsvg-convert, i need it. If you like this information, then you plan to get more information about [max verstappen transparent png renders] visit the web page.